Given a 512 Mbps link and a 20 msec propagation delay in the link. Find the tran
ID: 3859058 • Letter: G
Question
Given a 512 Mbps link and a 20 msec propagation delay in the link. Find the transmission time, utilization and throughput of the network if the network is using stop and wait transport protocol and a packet size of 4000 bit. Given a 512 Mbps link and a 20 msec propagation delay in the link. Find the transmission time, utilization and throughput of the network if the network is using Selective Repeat with window size of 20000 bits. Describe a case where Go Back N and STOP and WAIT have the same result. Draw a case in Selective Repeat where the Receiver receives the same sequence of packets for different sender sequences. Two Hosts X and Y send data to each other using TCP protocol. Draw the transaction of packets and ACKs between the two hosts. The segment size is 7 X sends: a b c d e f g h I j k l m n o p r s t u v w x y z a b c d e f g h j k Y sends: Z Y X W V U T S Q R P O N M L K J I H G F E D C B A Z Y X W U V T S RExplanation / Answer
Q1)
Tt(transmission time) = L/B
= (packet size)/Bandwidth
= 4000 bits/512 Mbps
=4000 bits/512*106 bps
=0.0078 msec
Tp (Propagation time) = 20 msec
a = Tp/Tt
= 20 msec/0.0078 msec
= 2564.10 msec
Throughput = 1/(1+2a)
= 1/(1+2*(2564.10))
= 1/(5129.20)
= 1.9496e-4
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