Given Data: average number of drops/mL = 73.0; overall average diameter of oleic
ID: 794254 • Letter: G
Question
Given Data: average number of drops/mL = 73.0; overall average diameter of oleic acid film = 38.0 cm. Use this data to calculate following:
a) average volume of oleic acid in film
b) volume of oleic acid per drop of solution
c) average area of oleic acid film
d) height of oleic acid film
e) volume of one oleic acid molecule
f) Avogadro's number
g) Percent disagreement
Formulas to be used:
1) Average volume of one drop of oleic acid solution:
V1 = 1.00 mL / average # of drops
2) Average volume of oleic acid in film in cm^3:
V2 = V1 x (0.0050 mL / 1 mL) x (1 cm^3 / 1 mL)
3) Height of oleic film in cm:
H = V2 in cm^3 / Average area of film in cm^3
* 1 mL = 1 cm^3
4) Volume of one oleic acid molecule in cm^3. A cubic shape is assumed:
V3 = H^3
5) Avogadro's number:
N = (282 g/mol) / (V3 x 0.895 g/cm^3)
6) Percent disagreement:
% dsgmt = [log(6.0225 x 10^23) - log(N)] / log(6.0224 x 10^23) x 100
Explanation / Answer
i keep getting a 100%+ disagreement which is unacceptable. i would like some help please. here are the results that i am getting: a) 6.8 x 10^-5 cm^3 b) 1.4 x 10^-2 ml c) 1134 cm^2 d) 6.04 x 10^-8 cm e) 2.203 x 10^-22 cm^3 f) 1.43 x 10^24 g) 100%+ error.
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