This excerise will be to simulate the parachute maneuvers performed in the movie

Question

This excerise will be to simulate the parachute maneuvers performed in the movie Eraser:

Given, the mass of John is 100 kg, the mass of the chute alone is 5kg. Assuming the body area of John Kruger to be 1 m2 and the area of the closed chute to be 0.5 m2, start by considering that John did not have a parachute, given his body area, it would take 90 seconds for him to reach the ground.

What would be his terminal velocity?

For the problem given above. At what height (in meters) was the airplane when John left it?

Using Octave or MATLAB;

Plot the position above the velocity for the chute and John in the scenario given above. Be sure to label all axes, use the legend command to label the lines. Open up the HTML editor and paste a screen shot of the graph in the editor window. Be sure to only paste just the plot itself, do not include borders or title and status bars.

Explanation / Answer

let terminal velocity be v. Then, assuming g = 10m/s2,

v = 10 *90 = 900 m/s

Height of plane = (1/2)*10*902 = 40500m

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