Consider a pressure-driven (Poiseulle) flow of a Newtonian fluid between two par

Question

Consider a pressure-driven (Poiseulle) flow of a Newtonian fluid between two parallel and stationary plates separated by a distance h = 1. Assuming the velocity distribution u(y) as a function of distance y measured from the bottom plate is given by u(y) = 5(y - y^2). Find the location y at which u(y) is maximum and the corresponding maximum velocity. Do it by creating a vector y with elements ranging from 0 to 1 and spacing 0.01. Then calculate u(y) for each value of y and find the maximum u(y) and associated y with MATLAB's built-in function 'max'.

Explanation / Answer

y = [0:0.01:1]

for i=1:100

u(i) = 5.*(y(i) - y(i).*y(i))

end

..max Value of u is

y = 1.2500

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