A mass spectrometer is designed to separate protein fragments.The fragments are
ID: 3897691 • Letter: A
Question
A mass spectrometer is designed to separate protein fragments.The fragments are ionized by removing a single electron and then enter a 0.80 T uniform magnetic field at a speed of 2.3
A mass spectrometer is designed to separate protein fragments.The fragments are ionized by removing a single electron and then enter a 0.80 T uniform magnetic field at a speed of 2.3 Atoms are ionized and accelerated. Ions of a particular velocity arc selected to enter ihe spectrometer. Ions of different masses follow paths of different radii. Only ions of a particular mass reach the exit slit and continue to the detector.
Explanation / Answer
Here's the COMPLETE answer:
Once the protein fragment is ionized (i.e. loses ONE electron) its electric charge is:
q = charge = 1.602 x 10^-19 Coulombs
The magnetic force exerted on the protein ion when it enters the mass spectrometer is given by:
F(magnetic) = q * v * B
Where
q = charge = 1.602 x 10^-19 C
v = protein ion's velocity = 2.3 x 10^5 m/s
B = strength of the magnetic field = 0.80 T
The situation simplifies because the direction of the magnetic field and velocity are perpendicular.
But we also note that the magnetic force is balanced by the centripetal force of the particle traveling IN A CIRCLE:
F(centripetal) = m*v^2 / r
m = mass of protein ion = 85 * mass of proton = 142 x 10^-27 kg
v = velocity = 2.3 x 10^5 m/s
r = radius of ion's path
When we equate the two forces we get:
m*v^2 / r = q*v*B
or
r = (m*v) / (q*B)
But the distance from the entrance of the ion to the point where it exits the magnetic field is 2*r (the DIAMETER of the circle is makes). Therefore:
D = distance = 2*r = (2*m*v) / (q*B)
= (2 * 142*10^-27kg * 2.3*10^5m/s) / (1.602x10^-19C * 0.80T)
so
D = 0.51m = 51 cm
So your answer is that the particle will exit the magnetic field 51 cm from where it entered.
P.S. I'm assuming the protein is only ionized ONCE - i.e. only ONE electron is stripped from the protein. This is usually the case.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.