A sculptor and his assistant stop for a break as they carry a marble slab of len

Question

A sculptor and his assistant stop for a break as they carry a marble slab of length L = 1.86 m and mass 67.5 kg up the steps, as shown in the figure. The mass of the slab is uniformly distributed along its length. As they rest, both the sculptor and his assistant are pulling directly up on each end of the slab, which is at an angle of 30 with respect to horizontal. What are the magnitudes of the forces that the sculptor and assistant must exert on the marble slab to keep it stationary during their break?

A) 330.9 N , 330.9N

B) 331.9 N , 331.9N

C) 330.5 N , 330.5N

Explanation / Answer

sum torque about bottom

m g L/2 cos(30) - F L cos(30) = 0

F = m g/2 = 67.5*9.81/2= 330.9 N

both will be the same so

so A)

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