A sculptor and his assistant stop for a break as they carry a marble slab of len
ID: 2264331 • Letter: A
Question
A sculptor and his assistant stop for a break as they carry a marble slab of length L=1.19m and mass 81.1kg up the steps, as shown in the figure. The mass of the slab is uniformly distributed along its length. As they rest, both the sculptor and his assistant are pulling directly up on each end of the slab, which is at an angle of 32.1
A sculptor and his assistant stop for a break as they carry a marble slab of length L=1.19m and mass 81.1kg up the steps, as shown in the figure. The mass of the slab is uniformly distributed along its length. As they rest, both the sculptor and his assistant are pulling directly up on each end of the slab, which is at an angle of 32.1 degree with respect to horizontal. What are the magnitudes of the forces that the sculptor and assistant must exert on the marble slab to keep it stationary during their break?Explanation / Answer
F1=F2
torque = LF
L being distance from pivot point to force
if you consider one person as the pivot and the remaining forces cancel each other out (since it is static) and the force done by the weight is in the middle of the length then
t=mg(L/2)-LF=0
mg(L/2)=LF
F =mg(L/2)/L
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