A simple electronic assembly consists of two components in a series configuratio

Question

A simple electronic assembly consists of two components in a series configuration with reliabilities as shown in the figure below.

Engineers would like to increase the reliability by adding additional components in one of the two proposed designs shown in the figure below (notice the difference in the diagram design with respect to being in series and parallel):

Find the reliability of the original design. Round your answer to four decimal places.

Explain how the configurations of the proposed designs differ.

-Select-Design option BDesign option CItem 2 places two components in series and duplicates this two-component series in a parallel and redundant configuration.-Select-Design option BDesign option CItem 3 places two redundant components in parallel and once they are collapsed we have composite reliabilities in a series configuration.

Find the reliabilities of Options B and C. Round your answers to six decimal places.
Realibility (Design Option B):  
Realibility (Design Option C):

Which proposed design has the best reliability?
-Select-Design option BDesign option CItem 6 has the best reliability.

Explanation / Answer

Here we have two sets of components which are connected in parallel. Each set consists of components with reliabilities 0.8 and 0.92 connected in series .

Reliability of each set( with components with reliabilities 0.8 and 0.92 connected in series ) will be = 0.8 x 0.92 = 0.736

Reliability of the system where two sets each with reliability 0.736 connected in parallel

= 1 – ( 1 – 0.736)^2

= 1 – 0.264 x 0.264

= 1 – 0.0696

= 0.9304

RELIABILITY OF DESIGN OPTION B = 0.9304

Here we have two sets of components connected in series . Each set consists of 2 items each with reliability 0.8 connected in parallel.

Reliability of each set as described above = 1 – ( 1 – 0.8) x ( 1 – 0.8) = 1 – 0.2 x 0.2 = 0.96

Therefore, reliability of the system where two sets each with reliability 0.96 are connected in series = 0.96 x 0.96 = 0.9216

RELIABILITY OF DESIGN OPTION C = 0.9216

Since design option B with reliability 0.9304 > design option C with reliability 0.9216 , proposed design B has the best reliability

DESIGN OPTION B HAS THE BEST RELIABILITY

RELIABILITY OF DESIGN OPTION B = 0.9304

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.