Only 3 questions! Thank you! ( Read questions please. It is different from the o

Question

Only 3 questions! Thank you! ( Read questions please. It is different from the other ones that have been posted)

Six months before its annual convention, the American Medical Association (AMA) must determine how many rooms to reserve. At this time, the AMA can reserve rooms at a cost of $100 per room. The AMA believes the number of doctors attending the convention will be has a triangular distribution with minimum value 2000, maximum value 7000, and most likely value 5000. If the number of people attending the convention exceeds the number of rooms reserved, extra rooms must be reserved at a cost of $ 160 per room. Assume that there are 8000 rooms available.

[Round your answers to the nearest integer. Also just enter the number. For example, if your answer is $123,456, then enter 123456 without $ and comma.]

Question 1 (2 points)

[Note that the numbers will change in the 2nd attempt.]

If they reserve 3,000 rooms now and the number of doctors attending the convention turns out to be 6,500, the number of extra rooms needed is

Your Answer:

Question 2 (2 points)

[Note that the numbers will change in the 2nd attempt.]

If they reserve 6,500 rooms now and the number of doctors attending the convention turns out to be 3,000, the number of extra rooms needed is

Your Answer:

Question 3 (2 points)

[Note that the numbers will change in the 2nd attempt.]

If they reserve 2,500 rooms now and the number of doctors attending the convention turns out to be 6,000, the total cost is

Your Answer:

Explanation / Answer

Cost of reserving a room = $100

Cost of reserving an extra room = $160

Ans 1)

Rooms reserved = 3000

Doctors attending convention = 6500

Number of extra rooms needed = 6500 - 3000 = 3500

Ans 2)

Rooms reserved = 6500

Doctors attending convention = 3000

The number of extra rooms needed would be equal to 0 as all the doctors attending the conference would have been adequately accommodated.

Ans 3)

Rooms reserved = 2500

Doctors attending convention = 6000

Number of extra rooms needed = 6000 - 2500 = 3500

Cost of reserving rooms initially = 2500 * 100 =$250000

Cost of reserving extra rooms = 3500 * 160 =$560000

Total cost = $250000 + $560000 = $810000

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