A conference is being held at a centre that has four different entrances. A regi

Question

A conference is being held at a centre that has four different entrances. A registration desk is being set up at each entrance. Assume that each desk will have its own queue and will see an equal portion of the expected 125 total customers per hour arriving at the conference (assume Poisson arrivals), and that customers will not line jockey between registration desks since they are significant distances apart. If each registration desk can serve one customer at a time, and the average time to serve a customer is 0.75 minutes, then what will be the average time that a customer waits in a line (in minutes) before being able to register?

a. 0.02 mins

b. 0.12 mins

c. 0.34 mins

d. 0.48 mins

e. 1.36 mins

Explanation / Answer

let's say, arrival rate = = 125 customer/ hr and service rate = µ = 0.75 min = 60/0.75 = 80 customer/ hr

now, average waiting time of customers in system Ws = 1 / (µ - )

= 1 / (125-80)

= 1/ 45 = 0.02 hrs

Answer : 0.02 hrs * 60 = 1.33 min.

Option e is correct answer

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