o. Items 12-13: Use the diagram at the right, in which PR is a diameter of 12. I
ID: 448925 • Letter: O
Question
o. Items 12-13: Use the diagram at the right, in which PR is a diameter of 12. If nQR = 500 then mQs- 13. IfSQ= 14, then TQ: 14. Finish the proof that BD is a diameter: Since mAB - mBC then ABCB by Theorem BE BE by Reflexive Property of Segment Congruence. Since AE·CE, then Since LAEC is a straight angle and mLEB = mLCEB, then both must be 90°, which makes BD L AC Thus BD is a diameter by Theorem . ABEe CBE by Postulate. 15. Explain how you know AB CD, given E is the center of the cirele. (Include Theorem numbers.)Explanation / Answer
12) If mQR = 50 Degree then mQS
Answer :
mQS is also 50 Degree because the segment which touch the QS points & PR points are perpendicular to each other.
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13) If SQ = 14 , TQ = ?
Answer :
TQ = 1/2 *SQ
=1/2 * 14
= 7
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14)
Answer :
Here I have just filled up the blanks.
mAB = mBC then AB = CB theorem by Segment & Side theorem
Triangle made at circle with perpendicular from top point to words front 2 corners.
Perpendicular theorem
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15)
Answer :
In the figure above, chords AB and CD are congruent. Therefore, their distances from the center, the lengths of segments EF and EG, are equal.
A final word on chords: Chords of the same length in the same circle cut congruent arcs. That is, if the endpoints of one chord are the endpoints of one arc, then the two arcs defined by the two congruent chords in the same circle are congruent.
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17 )
Answer :
Here I have just filled up the blanks.
<AEB is the central angle
<ADB & < ACB are the inscribed angles which intersect at A & B
<AB * BD Diameter
Inscribed angles theorem
m<2 = m<1 * M<3
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18)
Answer :
m<BAC = 90 -62 = 28 Degree
mAD= 180 -62-62 = 56 Degree
m<ABD = 180 -62 -90
= 28 Degree
m<DBC = 90 -28
= 62 Degree
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19)
Answer :
m<ABD = 58 - Degree
mCD = 180 - 58 - 58
= 64 Degree
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