Can someone help me please! This is for a Genetics Class. I tried this question

Question

Can someone help me please!
This is for a Genetics Class. I tried this question and I want to make sure I did it correctly
PLEASE HELP

As a conservation geneticist you're interested in preserving genetic diversity, especially among endangered populations, the most endangered of which appears to be desert pupfishes of northern Sonoran Mexico. You make scattered field collections ol 1UU individuals of one pupfish species, take a small clip of fin tissue, and then re ease e unharmed. You use PCR to study a particular gene locus of about 300 nucleo 1 es lacks introns. From sequencing the PCR products, you genotype all 1000 is o alleles that you discover, as follows. AA = 305 fish; Aa = 407 fish; aa = 288 What are the p and q values for the two alleles at this locus in this population?; define them respectively. Is this population in Hardy-Weinberg equilibrium (you must Supper your this answer using chi2 analysis and show all of your work below, or no points on this question)? Is there evidence of inbreeding in this population; if so, what is evidence and if not, then why not [Hint; consider the express,on Ft = 1 - Ht / Ho where Ho = HW expectation].

Explanation / Answer

From the data,

AA = 305

Aa = 407

Aa = 288

a.

According to the Hardy Weinberg equilibrium, p2+2pq+q2=1

Where, p equals all of the alleles in individuals who are homozygous dominant (AA) and the other half of the alleles in people who are heterozygous for the allele (Aa).

Therefore,

Similarly, q equals all of the alleles in individuals who are homozygous recessive (aa) and the other half of the alleles in people who are heterozygous for the allele (Aa).

Since,   

b.

From the data, the total number of individuals (n) = 305+407+288 = 1,000

So, the Hardy–Weinberg expectation is:

Therefore, Chi-square value is:

The degree of freedom = 1 (no. of genotypes – no. of alleles)

Since the p2+2pq+q2 is not equal to 1, the given population is not in Hardy Weinberg equilibrium.

c.

There is a chance of inbreeding in this population, as this population has deviated from Hardy Weinberg equilibrium. Inbreeding is a common cause for non-random mating, and it causes an increase in homozygosity for all genes.

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