Part A A: Effect Volume of LNazszol Volume of Volume Relative Trial of 0.150M Di

Question

Part A A: Effect Volume of LNazszol Volume of Volume Relative Trial of 0.150M Distilled of 6.00M Naas H2O HCI (mL) (mL mL [Nazszoal. Reaction Reaction Time Rate (sec) (sec) (M) (M) 25.00 0.00 5.00 125 5.00 Q25 12.50 Part B: Effect of LHC Relative Reaction Reaction Time Volume Volume of [Na2s2Osl Volume of 0.150M Distilled of 6.00M Trial H20 HCI Na2s2O, (sec) (M) (M) 5.00 100 400 -125 25.00 250 250 125 Os 5SYO 2.00 ,12.9 500 21.525 400 25.00 25.00 25.00 Part C: Effect of Temperature Rate Reaction Volume Volume Volume Reaction Rate Constant of 0.150M of of 6.00M Nazszol" (HCIT Time mmol (M) (M) (sec) Sec Temp Na2s20, Distilled HCI H2O Trial (mL) (mL) (mL) 1 5 1000 500 0.0500 1.00 15.00 4 30 10.00 15.00 5.00 loo 22 ols .cysn 5 40 10.00 15.00 5.00 .0500 6 50 10.00 15.00 5.00 occurs. Concentrations are after mixing, but before the reaction

Explanation / Answer

1) Rate law can be written as ...

Rate= k [HCL]^n [Na2S2O3]^m

2) Chloride displaces thiosulphate. In the first reaction thiosulphuric acid is formed. This is unstable and decomposes producing sulphur dioxide and solid sulphur that is forms the cloudy precipitate.The rate of the reaction depends on the concentrations of acid and sodium thiosulphate and on the temperature. & reaction will be of first order w.r.t. Na2S2O3.

3) Yes,  reaction will be of first order w.r.t.HCL.

4) rate law

Rate= k [HCL]^n [Na2S2O3]^m

k units-M/s, M/min, M/hr

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