please answer questions 1 and 2 Question 1: e atmosphere contains about 52 15 of

Question

please answer questions 1 and 2

Question 1: e atmosphere contains about 52 15 of air what in metric tons of mass carbon dioxide is in the atmosphere if the concentration of CO2 is 395 ppm? Question 2: A person who exercises vigorously several hours a day might take in about 22 m3 of air per day, A tree 33 m tall and 0.55 m in diameter at its base produces about 84,000 L of oxygen per year. How many people, breathing as described this way would five such trees supply with oxygen? (Please recall that 1 m 1000 L and that normally there's about 20% of oxygen in the air around.)

Explanation / Answer

1 ppm is equal to:

1g in 1g (or)

1mg in 1kg (or)

1kg in 1 tonne

1 tonne in 106 tonnes

Amount of air : 5.2 x 1015 tonnes

Amount of CO2: 395 ppm

So the amount of CO2 is 395 tonnes in in 106 tonnes of air, so the amount of CO2 present in 5.2 x 1015 tonnes is

= (5.2 x 1015 tonnes x 395 tonnes)/106 tonnes = 2.054 x 1012 tonnes

So, the mass of Carbon dioxide in the atomosphere if the concentration of CO2 is 395 ppm is          2.054 x 1012 tonnes

2.

Amount of air inhaled by one person per day is 22 m3 = 22000 L ( 1m3 = 1000L)

Amount of oxygen present in air is 20%, so the amount of oxygen inhaled and used by a person per day is

= (20/100) x 22000 = 4400 L

Each tree of the given dimension produce 84000 L of oxygen per year. So five trees produce (84000 L x 5) = 420000 L per year

So one person can survive on 5 trees for 420000 L /4400 L = 95.45 days = 95 days or

95 people can live on these 5 trees for one day.

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