The following mechanism has been proposed for the conversion of tert-buryl bromi

Question

The following mechanism has been proposed for the conversion of tert-buryl bromide to tert-buryl alcohol in aqueous solution: slow. (CH_3)_3 CBr rightarrow (CH_3)_3 C^+ + Br^- fast: (CII_3)_3 C^+ OII^- rightarrow (CII_3)_3 COII What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave ir. blank. Which species acts as a caralyst? Enter formula. If none, leave box blank: Which species acts as a reaction intermediate? Enter formula. If none, leave box blank Complete the rate law for the overall reaction that is consistent, with this mechanism. (Use the form k[A]^m[B]^u.... where 'I' is understood (so don't write It) for m, n etc.) Rate =

Explanation / Answer

Q1

simply, add all

(CH3)CBr --> (CH3)3C+ + Br-

(CH3)3C+ + OH- --> (CH3)3COH

adding all

(CH3)CBr+(CH3)3C+ + OH- -->  (CH3)3C+ + Br-+(CH3)3COH

cancel common terms

(CH3)CBr+(CH3)3C+ + OH- -->  (CH3)3C+ + Br-+(CH3)3COH

so

(CH3)CBr + OH- --> Br-+(CH3)3COH

Q2.

catalyst --> will not get consumed

Every specie is consumed, so no atalyst

Q3.

intermediates --> are consumed --> (CH3)3C+

Q4.

for this mechanism:

we must model the "SLOW" step

so

Rate = k*[(CH3)3CBr]

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