The following mechanism has been proposed for the conversion of tert-butyl bromi

Question

The following mechanism has been proposed for the conversion of tert-butyl bromide to tert-butyl alcohol in aqueous solution: step1 slow: (CH)CB(CH)3CBr step 2 fas: (CH3)3C+ + OH(CH)3COH 1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A]m[B]n , where T is understood (so don't write it) for m, n etc.) Rate =

Explanation / Answer

1)

overall reaction is obtained by adding both the steps

(CH3)3CBr + OH- —>(CH3)3COH + Br-

2)

Catalyst should be part of reactant in step 1 and product is step 2

There is no catalyst here

3)

(CH3)C+ is intermediate because it is produced in step 1 and used up in step 2

4)

rate depends on slowest step

Here 1st step is slowest

So, rate law is

rate = k [(CH3)3CBr]

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