please show ALL work. Dinitrogen tetraoxide is a colorless gas at room temperatu
ID: 486520 • Letter: P
Question
please show ALL work.
Dinitrogen tetraoxide is a colorless gas at room temperature. It can dissociate into nitrogen dioxide, which is a reddish brown gas. Three experiments were run starting with different initial amounts of N_2O_4(g) ([N_2O_4]_0 in the table). The systems were allowed to reach equilibrium and the concentrations for each gas were measured (in units of moles/Liter). For each of the boxes below, calculate the ratios indicated by the column heading. This will show the mathematical relationship that exists between the concentrations of NO_2 and N_2O_4 at equilibrium. Based on your calculations, indicate whether each statement is True (T) or False (F): Each experiment started with a different initial concentration of N_2O_4. The ratio ([NO_2]/[N_2O_4]) is equal to a constant value. The ratio (2 [NO_2]/[N_2O_4]) is equal to a constant value. The ratio ([NO_2]_2/[N_2O_4]) is equal to a constant value. Each experiment reached a different set of equilibrium concentrations.Explanation / Answer
Exp
[N2O4]0
[NO2]
[N2O4]
[NO2]/ [N2O4]
2 [NO2]/ [N2O4]
[NO2]2/ [N2O4]
1
3.5
2.85
2.1
2.85/2.1
=1.36
round this value
= 1.4
5.7/2.1
=2.71
round this value
= 2.7
8.12/2.1
=3.87
round this value
= 3.9
2
3.0
2.56
1.7
2.56/1.7
= 1.51
round this value
= 1.5
5.12/1.7
=3.01
round this value
= 3.0
6.55/1.7
=3.85
round this value
= 3.9
3
2.6
2.33
1.4
2.33/1.4
= 1.66
round this value
= 1.7
4.66/1.4
=3.33
round this value
= 3.3
5.43/1.4
=3.87
round this value
= 3.9
all the three experiment have different initial concentration( 3.5,3.0 & 2.6)
The ratio value of [NO2]/ [N2O4] in all three experiment have different value
1.4 , 1.5 & 1.7 is not a constant value.
3. Answer is FALSE
The ratio value of 2[NO2]/ [N2O4] in all three experiment have different value
2.7, 3.0 & 3.3 is not a constant value.
4.Answer is TRUE
The ratio value of [NO2]2/ [N2O4] in all three experiment have same value3.9, 3.9 & 3.9 is a constant value.
5. Answer is TRUE
Each having different set of Equilibrium concentration
Exp
[N2O4]0
[NO2]
[N2O4]
[NO2]/ [N2O4]
2 [NO2]/ [N2O4]
[NO2]2/ [N2O4]
1
3.5
2.85
2.1
2.85/2.1
=1.36
round this value
= 1.4
5.7/2.1
=2.71
round this value
= 2.7
8.12/2.1
=3.87
round this value
= 3.9
2
3.0
2.56
1.7
2.56/1.7
= 1.51
round this value
= 1.5
5.12/1.7
=3.01
round this value
= 3.0
6.55/1.7
=3.85
round this value
= 3.9
3
2.6
2.33
1.4
2.33/1.4
= 1.66
round this value
= 1.7
4.66/1.4
=3.33
round this value
= 3.3
5.43/1.4
=3.87
round this value
= 3.9
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