A student is givrn a stock solution of red dye that has a concentration of 5.682

Question

A student is givrn a stock solution of red dye that has a concentration of 5.682x10^-5 M. The student is asked to make five dilute solutions from this stock solution. Information for the five solutions is providen in the table below. Calculate the concentration of each solution, be sure to show your work very neatly below the table

Final

Concentration

(M)

Solution

2

Solution

3

Solution

4

Solution

5

Solution Name Volume Of Stock Final Volume

Final

Concentration

(M)

Solution 1 1mL 200mL

Solution

2

2mL 200mL

Solution

3

3mL 200mL

Solution

4

4mL 200mL

Solution

5

5mL 200mL

Explanation / Answer

Solution Name

Final

Concentration

(M)

Solution

2

Solution

3

Solution

4

Solution

5

explanation:

molarity of stock solution = C1 = 5.682 x 10^-5 M

stock solution volume for 1) = V1 = 1 mL

final volume = V2 = 200 mL

final concentration =C2 = ?

dilution formula : C1 V1 = C2 V2

5.682 x 10^-5 x 1 = C2 x 200

C2 = 2.841 x 10^-7 M

similary solve 2,3,4,5

Volume Of Stock Final Volume

Final

Concentration

(M)

Solution 1 1mL 200mL 2.841 x 10^-7

Solution

2

2mL 200mL 5.628 x 10^-7

Solution

3

3mL 200mL 8.523 x 10^-7

Solution

4

4mL 200mL 1.136 x 10^-6

Solution

5

5mL 200mL 1.421 x10^-6

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