What will the solution vapor pressure be for a solution of 2.23 mol of sucrose (

Question

What will the solution vapor pressure be for a solution of 2.23 mol of sucrose (C_12H_22O_11) dissolved in 1.000L of water at 20.0 degree C? The vapor pressure of pure water at 20.0 degree C is 17.5 torr. __ Osmosis is the net motion of a solvent toward a region of lower solvent concentration from a region of higher solvent concentration. Or otherwise stated: the net movement of a solute from a region of higher solute concentration to a region of lower solute concentration. The Important concept is that nature tries to disperse the solutes in a heterogeneous (liquid or gas phase) solution to produce homogeneous solution. This leads to a pressure that propels the components of the mixture. The equation used to describe this pressure is similar to the ideal gas law: Pi V = where n, R, T, and V have the same meanings as in the ideal gas law and Pi is the osmotic pressure and i is the van't Hoff factor. What is the osmotic pressure of 3.29 g of NaCl in 1.00 L of water at 20.0 degree C? ___

Explanation / Answer

P0-Ps/P0   = n solute/n solvent

no of moles of solute (sucrose) n solute = 2.23moles

no of moles of solvent (water)   n solvent = W/G.M.Wt = 1000/18 = 55.55moles

P0-Ps/P0   = n solute/n solvent

17.5-Ps/17.5   = 2.23/55.55

17.5-Ps        = 2.23*17.5/55.55

17.5-Ps      = 0.7025

   -Ps        = 0.7025-17.5

   -Ps      = -16.8

   Ps     = 16.8torr

b.

n   = w/G.M.wt = 3.29/58.5 = 0.056moles

NaCl --------> Na^+ + Cl^-

i=2

Piv = insT

Pi    = inST/V

        = 2*0.056*0.0821*293/1

     =   2.694atm

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