Calculate the vapor pressure of 3-pentanone (b.p. 102.0 °C) at the gas chromatog

Question

Calculate the vapor pressure of 3-pentanone (b.p. 102.0 °C) at the gas chromatography column temperature of 85.0 °C using the form of the Clausius-Clapeyron equation, where R is the ideal gas constant, Hvap is the enthalpy of vaporization, T1 and T2 are two different temperatures, and P1 and P2 are the vapor pressures at the respective temperatures. The enthalpy of vaporization can be estimated using Trouton's rule, H°vap = (88 J mol–1 K–1)·Tbp. Calculate the vapor pressure of acetone (b.p. 56.0 °C) at the same column temperature. (Put answers in Torr please!!!!)

Explanation / Answer

Enthalpy of vaporization = 88*375 = 33000 J/mol

Initial pressure = 760 Torr and initial temperature = 375 K

Final temperature = 358 K

Ln(p2/p1) = delta H/R x ( 1/T1 - 1/T2)

P2 =p1 * exp( 33000/8.314 x ( 1/375 - 1/358) )

= 760* 0.6049

= 459.75 torr

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