The answer is C, not sure why. I calculated Q as 1, therefore the reaction shoul

Question

The answer is C, not sure why.

I calculated Q as 1, therefore the reaction should shift left to create more reactants since Q>K?

32. For the reaction: 2 HI(g) H2(g) L(g), Ke 0.020 at 720 K. If the initial concentrations of HI, H2, and I2 are all 1.50 x 10 M at 720 K, which one of the following is correct? A. The system is at equilibrium. B. The concentrations of H, and I, will decrease as the system is approaching equilibrium. C. The concentration of HI will decrease as the system is approaching equilibrium.

Explanation / Answer

Qc = 1

Since Qc > Kc, the equilibrium will shift to left

So, [HI] will increase and [H2], [I2] will decrease

Answer: B

The answer must be B

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