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Composition (at% sn) 327°C 300 Liquid a +L 200 a 183 C 61.9 18.3 100 60 Composit

ID: 497486 • Letter: C

Question

Composition (at% sn) 327°C 300 Liquid a +L 200 a 183 C 61.9 18.3 100 60 Composition (wt% Sn) (Pb) Aloy A Liquidus Temperature Eutectic Temperature 180 Solidus Temperature 180 Sold fication lot freeaing) range of alloy. Melt Superheat (inital melting temp Liquidus) Elapsed time at liquidus temp Elapsed time at eutectic or solidus temp 1015 Local solidification time (Elapsed time at Eutecto tempo -Elapsed tme at Liquidus Temp) Solidifcation rate (Freezing range local solidification time) Celcius/min 29508 100 B +L 978 300 100 100 (Sn) Alloy B Alloy C Alloy D 179 179 610 48828 24500 20160

Explanation / Answer

You find the answers by drawing lines in the diagrama referrin to the data given in the problem for the first alloy:

1) First draw a horizontal line at 210 C

2) Draw a vertical line from the liquid line to the solid line, it has to represent 30 C units

3) In order to find the composition draw a vertical line that represents 40 C

This drives you to a composition of aproximately 48% of Sn and 52% (100 - 48) of Pb

For the second alloy we can see that the compound is a solid that´s why we are not given the eutectic temperature that means that it can has 98% of Sn or 17.5% of Sn

Draw 2 lines of 59C from the liquidus temperature line to the solidus temperature line, one on the left and other on the right.

Now draw and match the line of melting superheat of 21C, you can only draw it on the right son the composition must be 98% of Sn and 2% approximately

For Alloy C if we follow the same steps as alloy 1 we find that there´s aproximately 42.5% of Sn and 57.5% of Pb

For Alloy D if we follow the same steps as alloy 1 we find that there´s aproximately 41.8% of Sn and 58.2% of Pb

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