When excited luminol loses energy to return to its ground state, a blue light is

Question

When excited luminol loses energy to return to its ground state, a blue light is emitted. When a sensitizer molecule is added to the solution (see scheme below), excited luminol transfers all its energy to the sensitizer, thus exciting the sensitizer, while returning to its ground state. Then, the excited sensitizer emits a radiation to return to its own ground state. Will the wavelength of the light emitted from the sensitizer be higher or lower than that of the blue light emitted from luminol alone? Why?

Explanation / Answer

There may be two cases.

1. If sensitizer was in gound state initially then the emited wavelength will be same as there is no evidence of loss of energy.

2. If sensitiger is already in exited state then wavelength will be lower

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