equivalent ation of Na0H Solution significant mL) mL R.ombrios 5.oo mu mL mL. a.
ID: 499808 • Letter: E
Question
equivalent ation of Na0H Solution significant mL) mL R.ombrios 5.oo mu mL mL. a.OAT2 Trial 1.5 2 50mL3or Trial 1 figures) 0.02 mLI (to (to (to (to (to (to nearest 0.02 0.02 0.02 0.02 0.02 mL) mL mL reading of acid solution reading of acid solution of acid solution delivered of acid solution (to four reading of base solution reading of base solution of base solution delivered of base solution Normality of base solution of Solid Acid Unknown number paper paper and solid acid Acid reading of base solution reading of base solution standardized base used of standardized base solution of base consumed of acid weight of unknown acid equivalent weight of unknown acid the details of all calculations; use extra sheets if necessary. 55Explanation / Answer
Calculation for Trial 1 :
N1V1 = N2V2 where N1 and V1 is the concentration and volume of base . N2 and V2 is the concentration and volume of the acid.
N1 * 10.50 mL = 0.0172 N * 10mL
or, N1 = 0.0172 N * 10mL/10.50mL = 0.0164 N
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Calculations for trial 2
N1V1 = N2V2
or, N1 = 0.0172 N * 10mL/6.5mL = 0.026 N
Averate = 0.0212 N
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