equivalence volume= 11.9 mL, moles of NaOH used: 1.2X10^-3 using the equivalence

Question

equivalence volume= 11.9 mL, moles of NaOH used: 1.2X10^-3

using the equivalence volume and molarity of base used, calculate the concentration of acid in your original unknown (that is, the original 10.0 mL of unknown acid before it was diluted with the 10.00 mL water)

[HA]original= ?

in order to calculate your Ka from the inital pH you recorded before adding any base, you must take into account the fact that you diluted your original solution by adding 10.00 mL of deionized water before recording the pH. the concentration of this solution is therefore half of the concentration of the original solution

[HA] diluted=?

Explanation / Answer

a)concentration of acid=11.9*1.2*10^-3 =14.28*10^-3miliM

b)HA dil.=7.14*10^-3 miliM

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