Help with number 6. Molar Solubility, Common-Ion Effect. Laboratory Questions Ci

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Help with number 6. Molar Solubility, Common-Ion Effect.

Laboratory Questions Circle the questions that are to be answered. i. A-2. Suppose some of the solid calcium hydroxide is inadvertently transferred along with the supernatant liquid for analysis. a. more, less, or the same amount of hydrochloric acid titrant be used for the analysis in Part A.6? Explain. b. Will this inadvertent transfer increase, decrease, or have no effect on the calculated so product for calcium c. Will this inadvertent transfer increase, decrease, or have no effect on the calculated molar solubility of calcium hydroxide Explain. 2. Part A.6. Does adding boiled, deionized water to the tit flask to wash the wall of the Erlenmeyer flask and the buret tip increase, decrease, or have no effect on the Ks Value of the Ca(OH)2? Explain. 3. Part A 6. While titrating the saturated Ca(oH), solution, Isabella was distracted, and the endpoint was surpassed-a dark red-orange. As a result of this technique enror, will the reported molar solubility of Ca(oH): be too high or too low? Explain. *4. Part B.1. How will using tap water instead of boiled, deionized water affect the Ksp value of Ca(oH)r increase, decrease, or have no effect? Explain. Hint: How will the minerals in the water affect the solubility of Ca(OH)? 5. Part A 8. Jerry forgot to record the actual molar concentration of the standard HCl solution (which was actually 0.044 M). However, to complete the calculations quickly, the -0.05 M concentration was used. Will the reported molar solubility of too high or too low 6. The ethylenediaminetetraacetate ion, H.Y2, forms a strong complex with the calcium ion. How does the addition of Y2-affect the molar solubility of Ca(OH.? Explain. See Experiment 21 for the reaction of Ca with H2Y? 27o Molar solubility, Common-lon Effect

Explanation / Answer

Q6.

The complx:

H2Y-2 can act as an ACID since it coul donate H+ ions

note that Ca(OH)2 <-> Ca+2 + 2OH-

so

H+ + OH- -- H2O(l)

if this is the case, then

solubility of Ca(OH)(s) increases, since OH- reacts, so the shift of equilibrium goes towad more Ca+2 and OH- production

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