Calculate the final concentration of iron (III) in the five 10ml solutions you m

Question

Calculate the final concentration of iron (III) in the five 10ml solutions you made.

concentration of HCl= 2M
concentration of KSCN= 1.5 M
concentration of FeCl3= 0.00025 M
(I would just like a walk through of solving for one so I know how to do the rest)

test tube.                 1.    2.    3.     4.     5.
volume hcl(ml)        4.    3.    2.     1.    0
volume FeCl3(ml)    1.    2.    3.    4.    5
volume KSCN(ml)    5.    5.    5.    5.    5

spondina test tubes. Ritee the Iliti tuhe Rinse the slici N vipele ip wilh aivalilled water aazn. virally, the to volume 5.0 mL. 2.0 m 5.0 mL 4.1 mL 5 mL.

Explanation / Answer

Let us work with the solution in test tube #2. Put down the volumes of the solutions that go into test tube#2.

Vol. of 2 M HCl = 3.0 mL

Vol. of 0.00025 M FeCl3 = 2.0 mL

Vol. of 1.5 M KSCN = 5.0 mL

Total volume of solution = (3.0 + 2.0 + 5.0) mL = 10.0 mL.

Use the dilution equation to calculate the final concentration of Fe (III):

(2.0 mL)*(0.00025 M) = (10.0 mL)*[Fe (III)]final

===> [Fe (III)]final = (2.0 *0.00025 M)/(10.0) = 0.000050 M

The concentration of Fe (III) in the test tube is 5.0*10-4 M (ans).

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