Molarity = 0.50 M NaOCl solution and 0.50 M Na2S2O3 solution Determine the whole

Question

Molarity = 0.50 M NaOCl solution and 0.50 M Na2S2O3 solution

Determine the whole number mole ratio of the two reactants. The molarities of the reactant solutions were equal in this experiment. Is this necessary, or even important, for the success of the experiment? Which solution was the limiting reactant in each trial? Find the actual balanced chemical equation for the reaction between OCl^- and S_2O_7^3- in basic solution. Does the mole ratio that you determined in your experiment match the actual reaction equation's coefficients for the two reactants? Explain, especially if your mole ratios do not match the coefficients.

Explanation / Answer

1.

Moles of OCl- = Molarity * Volume in liter

= 0.5 * 0.04 (considering second run)

= 0.02 moles

Moles of S2O32- =

Molarity * Volume in liter

= 0.5 * 0.01 (considering second run)

= 0.005 moles

Therefore, mole ratio = 0.02/0.005

= 4

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