O 4/3/2017 05:00 PM A 8.4/10 Gradebook Print Calculator Periodic Table X Incorre
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O 4/3/2017 05:00 PM A 8.4/10 Gradebook Print Calculator Periodic Table X Incorrect Question 7 of 10 Incorrect Map Sapling Learning Calculate the pH for each of the following cases in the titration of 35.0 mL of 0.220 M NaOH(aq), with 0.220 M HBr(aq). Number Note: Enter your answers with two decimal places. 11.88 (a) before addition of any HBr Number 12.99 (b) after addition of 13.5 mL of HBr Number 12.75 (c) after addition of 20.5 mL of HBr Number (d) after the addition of 35.0 mL of HBr 7 Number (e) after the addition of 40.5 mL of HBr 1.79 Number after the addition of 50.0 mL of HBr 0.657 Ae Previous & Give Up & View solution Try Again Next d Exit ExplanationExplanation / Answer
a) initially only NaOH present
as NaOH strong base
[NaOH] = [OH-] = 0.220 M
pOH = - log [OH-]
pOH = - log [0.220]
pOH = 0.66
pH = 14 - 0.66
pH = 13.34
f) millimoles of NaOH = 35 x 0.22 = 7.7
millimoles of HBr added = 50 x 0.22 = 11
11 - 7.7 = 3.3 millimoles of HBr left
[3.3 / 85] = 0.039 M
as HBr is strong acid
pH = - log [H+]
pH = - log [0.039]
pH = 1.41
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