Calculate the molar solubility of silver chloride CdCl(s), knowing that its p_K_

Question

Calculate the molar solubility of silver chloride CdCl(s), knowing that its p_K_sp = = 28.85. Calculate the solubility product of barium sulfate BaSO_4, knowing that its solubility in pure water is 1.0 times 10^-5 M. Knowing that p_K_sp of cupper hydroxide Cu(OH)_2(s) is 19.36, calculate: (a) the solubility of Cu(OH)_2 in pure water, (b) the [Cu^+] at pH 4, and (c) the [Cu^2+] at pH 11. The solubility of MgCO_3(s) in pure water is 6.32 times 10^-3 M. What is the solubility of MgCO_3(s) if you add 5 time 10^-3 M MgCl_2?

Explanation / Answer

Q1.

Find molar solubility of CdCl(s)

It will dissociate as follows

CdCl(s) --> Cd+(aq) + Cl-(aq)

the Ksp is given by

Ksp = [Cd+][Cl-]

1 mol of CdCl = 1 mol of Cd = 1 mol of Cl

let "s" be solubility so

S = S mol of CdCl = S mol of Cd = S mol of Cl

Ksp = 10^-pKsp = 10^-28.85

substitute

10^-28.85 = S*S

S = sqrt(10^-28.85)

S = 3.758*120^-15 M

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