A 250.0 microlitre solution was formed using 25.0mg of an unknown solid. 50 micr

Question

A 250.0 microlitre solution was formed using 25.0mg of an unknown solid. 50 microliter was taken out of the solution and diluted to 1.000ml. The concentration of the final solution was determined to be 54.0mM. what is the molar mass of the unknown solild? A 250.0 microlitre solution was formed using 25.0mg of an unknown solid. 50 microliter was taken out of the solution and diluted to 1.000ml. The concentration of the final solution was determined to be 54.0mM. what is the molar mass of the unknown solild? A 250.0 microlitre solution was formed using 25.0mg of an unknown solid. 50 microliter was taken out of the solution and diluted to 1.000ml. The concentration of the final solution was determined to be 54.0mM. what is the molar mass of the unknown solild?

Explanation / Answer

volume of solution = 250 uL

concentration = C1

volume of solution diluted = 50 uL

diluted to = 1.000 mL = 1000 uL

concentration C2 = 54.0 mM

C1 V1 = C2 V2

C1 x 50 = 54 x 1000

C1 = 1080 mM

concentration of initial solution = 1080 mM

concentration = moles / volume

1080x 10^-3 = moles / 250 x 10^-6

moles = 2.7 x 10^-4

mass / molar mass = 2.7 x 10^-4

25 x 10^-3 / moalr mass = 2.7 x 10^-4

molar mass of unknown solid = 92.6 g/mol

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