The vapor pressure of an aqueous solution is found to be 24.9 mm Hg at 25 degree
ID: 507032 • Letter: T
Question
The vapor pressure of an aqueous solution is found to be 24.9 mm Hg at 25 degree C. What is the mole fraction of solute in this solution? The vapor pressure of water is 25.756 mmHg at 25 degree C a. 0 967 b. 1.03 c. 0.034 d. 0.976 e. 0.033 Hard water, which contains Mg^2- and Ca^2+ ions, tends to form a ring in a bathtub due to its reaction with soluble anions in soap. The formation of this insoluble material is an example of ___ a. a decomposition reaction b. a redox reaction c. an acid base reaction d. a combustion reaction. e. a precipitation reaction. Which of the following solutions is isotonic with the solution inside a red blood cell, which has an osmotic pressure of 7.89 atm at 37.0 degree C? a. 0.310 M calcium chloride(CaCl_2) b. 0.155 M sodium phosphate (Na_3PO_4) c. 0.155 M glucose (C_6H_12O_5) d. 0.310 M sodium acetate (NaCH_3COO) e. 0.155 M potassium chloride (KCI) What are the products in the molecular equation for the complete neutralization reaction of aqueous barium hydroxide and nitric acid? a. BaNO_3(aq) + H_2O(l) b. BaN_2(s) + 2 H_2O(l) c. BaH_2(aq) + 2NO(g) d. Ba(NO_3)_2(aq) + 2 H_2O(l) e. Ba_2O(s) + H_2O(l) + 2NO_2(g) What is the oxidation number of carbon in the bicarbonate ion (HCO_3^-)? a. -4 b. -2 c. +1 d. +4 e. +2 Indicate winch aqueous solution has the slowest evaporation rate. a. 0.2 M NaCl b. 0.1 M KCI c. 0.2 M NaCO_3 d. .1 M NaBr e. 0.1 M MgCl_2 Calcium hydroxide is slightly soluble in water, About 1 gram will dissolve in 1 liter. What are the spectator ions in the reaction of the such a dilute solution of calcium hydroxide with hydrochloric acid? a. H_3O^- and OH^- b. Ca^2+, Cl^-, H_3O^+, and OH^- c. Ca^2+ and Cl^- d. Ca^+ and OH^- e. H_3O^+ and Cl^- You must use 168 g of carton disulfide (CS_2 76.13 g/mol) with acetonitrile (CH_2CN, 41.06 g/mol) to create a solution that has a total vapor pressure of 292 torr at 25 degree C. Calculate the number of grams of CH_2CN required. a. 40.6 g b. 90.6 g c. 42.1 g d. 4.93 g e. 29.1 gExplanation / Answer
Ans 15 e. 0.033
the mole fraction can be be calculate using formula
x = (P° - P) / P°
x = (25.756 - 24.9) / 25.756
x = 0.033
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