Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

The Nernst equation relates a nonstandard potential, E, to the standard potentia

ID: 510781 • Letter: T

Question

The Nernst equation relates a nonstandard potential, E, to the standard potential, E, and the reaction quotient, Q, by E=E2.303RTnFlogQ=E0.0592 VnlogQ where R=8.314 J/(molK), T is the Kelvin temperature, n is the number of moles of electrons transferred in the reaction, and F=96,485 C/mol e.

Part A

At 68.0 C , what is the maximum value of the reaction quotient, Q, needed to produce a non-negative E value for the reaction SO42(aq)+4H+(aq)+2Br(aq)Br2(aq)+SO2(g)+2H2O(l) In other words, what is Q when E=0 at this temperature? Express your answer numerically to two significant figures.

From each of the following pairs of substances, use data in Appendix E in the textbook to choose the one that is the stronger reducing agent.

Fe(s) or Mg(s).

or .

SubmitMy AnswersGive Up

Part B

Ca(s) or Al(s).

or .

SubmitMy AnswersGive Up

Part C

H2 (g, acidic solution) or H2S(g).

(, acidic solution) or .

H2S(g)

Cl2(g) or Br2(l).

or .

SubmitMy AnswersGive Up

Part B

Zn2+(aq) or Cd2+(aq).

SubmitMy AnswersGive Up

Correct

Part C

Cl2(g) or ClO3(aq).

or .

SubmitMy AnswersGive Up

Part D

H2O2(aq) or O3(g).

or .

From each of the following pairs of substances, use data in Appendix E in the textbook to choose the one that is the stronger reducing agent.

Fe(s) or Mg(s).

or .

Fe(s) Mg(s)

SubmitMy AnswersGive Up

Part B

Ca(s) or Al(s).

or .

Ca(s) Al(s)

SubmitMy AnswersGive Up

Part C

H2 (g, acidic solution) or H2S(g).

(, acidic solution) or .

H2 (g, acidic solution)

H2S(g)

Cl2(g) or Br2(l).

or .

Cl2(g) Br2(l)

SubmitMy AnswersGive Up

Part B

Zn2+(aq) or Cd2+(aq).

Zn2+(aq) Cd2+(aq)

SubmitMy AnswersGive Up

Correct

Part C

Cl2(g) or ClO3(aq).

or .

Cl2(g) ClO3(aq)

SubmitMy AnswersGive Up

Part D

H2O2(aq) or O3(g).

or .

H2O2(aq) O3(g)

Explanation / Answer

Ans (A)- E=E2.303RT /nF x(logQ)

is the nernst equation -

given that -

T = 68 degree celcius = 273 + 68 = 341 kelvin

n = no of moles

for the given reaction n = 2

standard potential for the given reaction is

E0(degrees) = -.87 V

so putting the following terms in the equation =

0 = -.87 - (8.31 J /(mol K) x 341 K x2.303 ) / (2 x 9.65 x 10x4 C ) x log Q

Q = 1.821x10-26

Mg(s) is stronger reducing nature

Ans (B) Ca is stronger reagent than Al

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote