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I need help finishing this! I took a picture of the first page just in case it's needed! Blank 3. do Trial 3 Trial 1 Trial 2 Titration of EDTA solution 25.0 ml. 250 mi 25.0 mL volume of Caco solution titrated mol/L 239 moles 239 moles .239 moles Moles of Caco titrated Moles of ca titrated Initial buret reading o. o. mu 13 mu Final buret reading 40 mL 34.30 mu mu 34.20 mL. 28.9 mL Volume of EDTA dispensed mL volume of EDTA used to titrate ca 3%. 50 mu 31 oo mL 25.34 -Moles of EDTA used to titratecaer moles moles moles 239 mollu 2.39 mol/L 229 mollu Molarity of EDTA mol/L of EDTA Average Mola Moles of Cacon titrated R Molarity of Cacosxvolume of Cacos titrated oogs 2s.0mL 239 moles (3 trials) EDTA used to titra mole Molarity of EDTA solution volume of EDTA used to titrate ca 25.39 31.00 30.80 Average Molarity of M of E t M of EDT alzt M of EDT EDTA solution

Explanation / Answer

Thanks for adding a picture of page # 1. It was very helpful.

1.) Molarity of CaCO3 solution is the same as the one you have written on page # 1 : 0.00956 M or 0.00956 mol/L.

2.) # of moles of CaCO3 titrated = Molarity of CaCO3 X volume of CaCO3 titrated (FYI: molar mass of CaCO3 = 100.0869 g/mol)

# of moles of CaCO3 titrated = 0.00956 mol/L X 25 ml

# of moles of CaCO3 titrated = 0.00956 mol/L X 0.025 L (Convert volume of CaCO3 titrated from ml to litres)

# of moles of CaCO3 titrated = 2.39 X 10-4 moles

3.) Moles of Ca2+ titrated = 0.239 g X (1 mol of CaCO3 / 100.0869 g/mol) X (1 mol Ca2+ / 1 mol CaCO3)

Moles of Ca2+ titrated = 0.00239 moles

4.) Moles of EDTA used to titrate Ca2+ = moles of Ca2+ titrated X (1 mol of EDTA / 1 mol of Ca2+)

Moles of EDTA used to titrate Ca2+ = 0.00239 moles of Ca2+ X  (1 mol of EDTA / 1 mol of Ca2+)

Moles of EDTA used to titrate Ca2+ = 0.00239 moles

5.) Molarity of EDTA solution = moles of EDTA used to titrate Ca2+ / volume of EDTA used to titrate Ca2+

Trial 1, Molarity of EDTA solution = 0.00239 moles / 36.80 ml = 0.00239 / 0.03680 L = 0.065 M

Trial 2, Molarity of EDTA solution = 0.00239 moles / 0.031 L = 0.077 M

Trial 3, Molarity of EDTA solution = 0.00239 moles / 0.02539 L = 0.0941 M

6.) Average molarity of EDTA solution = (0.065 + 0.077 + 0.0941) / 3

Average molarity of EDTA solution = 0.0787 M

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