Table 1 chromatographic conditions under which a separation liquid was carried o
ID: 513469 • Letter: T
Question
Table 1 chromatographic conditions under which a separation liquid was carried out Column length Column inner 30 cm Volumetric diameter (ID) 4.6 mm Flow rate volume 0.850 mL/min of mobile phase (VM 1.37 mL volume of stat. phase IV) 0.164 mL Type of detector UV/vis Table 2 summarizes chromatographic collected for a four component mixture. For the calculations data that follow it will be useful to complete the last column of the table Retention time (min) Width of peak base, retention time min peak width 3.1 Non-retained 0.41 12.43 1.07 13.3 12 I 14.1 1.16 12, So 1.72 21.6Explanation / Answer
a). Average linear velocity of molecules in mobile phase = (Column Length * Volume flow rate ) / Volume of mobile phase
= ( 30 cm * 0.850 mL/min) / 1.37 mL
= (25.5 / 1.37) cm / min
= 18.61 cm / min
b). Component A is retained the least. Since it remains in the column for the shortest duration of time.
c). Average Linear Velocity of A (cm/min) = Length of the column / Retention Time of A
= 30 cm / 5.4 min'
= 5.5 cm / min
f). The Component D is retained the most. Since it remains in the column for the longest duration of time.
g). The average linear velocity of D (cm/min) = Length of the column / Retention time of D
= 30 cm / 21.6 min
= 1.38 cm/min
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