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Please show all work and explain. Thank you! Sapling Learning AGOf Substance (kJ

ID: 516098 • Letter: P

Question

Please show all work and explain. Thank you!

Sapling Learning AGOf Substance (kJ/mol) Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M203 9.30 M(s) O2(g) What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? Number AGO. kJ mol What is the equilibrium constant of this reaction, as written, in the forward direction at 298 K? Number What is the equilibrium pressure of O2(g) over M(s) at 298 K? Number atm Map

Explanation / Answer

M2O3 (s) <-----> 2M(s) + 3/2 O2 (g)

dG rxn = dG products - dG reactants

dG rxn = (2*0 + 3/2*) - (1*(-9.3))

dG rxn = 9.3 kJ/mol

dG = -2.303RTlogK

9.3 * 10^3 = -2.303 * 8.314 * 296 log K

K = 0.02286

Kp = Kc * (RT)^dn (dn = gas product moles - gas reactant moles)

Kp = 0.02286 * (0.0821 * 296)^(3/2-0)

Kp = 2.7386

we know Kp = ((po2)^3/2 * pM)/p M2O3

here M and M2O3 are solids so their pressure is considered as unity.

2.7386 = (pO2)^3/2

pO2 = 1.9574 atm

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