Please show all work and explain. Thank you! Sapling Learning AGOf Substance (kJ
ID: 516098 • Letter: P
Question
Please show all work and explain. Thank you!
Sapling Learning AGOf Substance (kJ/mol) Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M203 9.30 M(s) O2(g) What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? Number AGO. kJ mol What is the equilibrium constant of this reaction, as written, in the forward direction at 298 K? Number What is the equilibrium pressure of O2(g) over M(s) at 298 K? Number atm MapExplanation / Answer
M2O3 (s) <-----> 2M(s) + 3/2 O2 (g)
dG rxn = dG products - dG reactants
dG rxn = (2*0 + 3/2*) - (1*(-9.3))
dG rxn = 9.3 kJ/mol
dG = -2.303RTlogK
9.3 * 10^3 = -2.303 * 8.314 * 296 log K
K = 0.02286
Kp = Kc * (RT)^dn (dn = gas product moles - gas reactant moles)
Kp = 0.02286 * (0.0821 * 296)^(3/2-0)
Kp = 2.7386
we know Kp = ((po2)^3/2 * pM)/p M2O3
here M and M2O3 are solids so their pressure is considered as unity.
2.7386 = (pO2)^3/2
pO2 = 1.9574 atm
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