How many moles of sodium acetate must be added to 500 0 mL of 0 250 M acetic aci

Question

How many moles of sodium acetate must be added to 500 0 mL of 0 250 M acetic acid solution to produce a solution with a pH of 4 94? (The pK_a of acetic acid is 4 74) a 0.011 moles b 0.021 moles c. 0.13 moles d 0 20 moles e. 0.21 moles The solubility product for Al(OH)_3 is written as _. a. K_a = [Al][OH] b. K_a = [Al][OH]/[Al][(OH)_3] c. K_a = {Al^3] 3[OH] d. K_e = [Al^3] + [OH] e. K_e = [A] 3 [OH]/[A(OH)] The solubility product for Ag PO_4. is written as _ where s is the molar solubility. a. K_10 = s^2 b. K_10 = 4s^3 c. K_10 = 27 s^4 d. K_10 = 3s^3 e. K_10 = 3s^4 Lead pipes were used at one tune for delivering drinking water What is the maximum possible concentration of lead in the water if it comes from lead (II) hydroxide (K_10 = 2 8 times 10^-16) dissolving from the surface of the pipes? Note that the EPA limit on lead m drinking water is 7.2 times 10^4 M a. 4.1 times 10^-6 b. 1.6 times 10^-6 M c. 6.5 times 10^-6 M d. 5.1 times 10^-6 M e. 8.3 times 10

Explanation / Answer

22.

pH of a buffer solution can be calculated as

pH = pka + log [acetate/acetic acid]

or, 4.94 = 4.74 + log [acetate/acetic acid]

or, [acetate/acetic acid] = 1.58

Initial moles of acetic acid = 0.5L * 0.25 M =0.125 moles

Suppose x moles of sodium acetate is added.

x/0.125 = 1.58

or, x = 0.198 moles = 0.2 moles

option (d)

                                                         

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