Calculate the number of moles of aluminum that you used. Show your calculations:

Question

Calculate the number of moles of aluminum that you used. Show your calculations: __________ moles Al Calculate the molar mass of alum: ________________ g/mole Noting that one aluminum atom is in each formula unit of alum, we know that each mole of aluminum will give rise to one mole of alum. Based on the number of moles of aluminum you used, calculate the maximum number of grams of alum that you could produce (theoretical yield), and assuming that aluminum is the limiting reagent: (show your work)

Explanation / Answer

Mass of alumnium foil = Mass of (foil + flask) - mass of flask = 124.071 - 123.51 = 0.561 g

Molar mass of alumnium = 27 g/mol

No. of moles of Alumnium = Mass / molar mass = 0.561 g / 27 g/mol = 0.021 moles Answer

formula of alum is KAl(SO4)2·12H2O

Molar mass of alum = 39.1 + 27 + 2 * (32.06 + 4*16) + 12 ( 2*1.00794 + 16) = 474.38 g/mol Answer

No. of moles of alum = No. of moles of Alumnium = 0.021 moles

Theoretical yield = Mass of alum = No. of moles * Molar mass = 0.021 moles * 474.38 g/mol = 9.96 g Answer

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