The quantity of antimony in an ore can be determined by an oxidation-reduction t

Question

The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentration acid and passed over a reducing agent so that all the antimony is in the form Sb^3+ (aq). The Sb^3+ (aq) is completely oxidized by an aqueous solution of BrO^-_3 (aq). Complete and balance the equation for this reaction in acidic solution. BrO^-_3 + Sb^3+ rightarrow Br^- + Sb^5+ If you need to clear your work and reset the equation, click the button that looks like two red arrows.

Explanation / Answer

Sb3+ + BrO3- = Sb5+ + Br-

split

Sb+3 = Sb+5

BrO3- = Br-

balance O

Sb+3 = Sb+5

BrO3- = Br- + 3H2O

balance H+

Sb+3 = Sb+5

6H+ + BrO3- = Br- + 3H2O

balance charges

Sb+3 = Sb+5 + 2e-

6e- + 6H+ + BrO3- = Br- + 3H2O

balance e-

3Sb+3 = 3Sb+5 + 6e-

6e- + 6H+ + BrO3- = Br- + 3H2O

add all

3Sb+3 + 6e- + 6H+ + BrO3- = Br- + 3H2O + 3Sb+5 + 6e-

cancel e-

3Sb+3 + 6H+ + BrO3- = Br- + 3H2O + 3Sb+5

this is now balanced

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