The quantity of antimony in an ore can be determined by an oxidation-reduction t

Question

The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form Sb3 (aq). The Sb3 (aq) is completely oxidized by an aqueous solution of BrO3(aq). Complete and balance the equation for this reaction in acidic solution.

Explanation / Answer

here is the balanced equation 6H+(aq) + BrO3¯(aq) + 3Sb3+(aq) ---> Br¯(aq) + 3Sb5+(aq) + 3H2O(l) moles of bromate in the titration = .125 x .0432 moles = 0.00540 moles these react with 3 x 0.00540 moles of Sb at the eq point = 0.0162 moles of Sb3+ Molar mass of Sb is 121.7g/mol so mass of Sb = .0162 x 121.7 g = 1.972 g % Sb = 1.972 / 9.51 = 20.7%

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