The quantity of antimony in an ore can be determined by an oxidation-reduction t

Question

The quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dissolved in hot, concentrated acid and passed over a reducing agent so that all the antimony is in the form Sb3+ (aq). The Sb3+ (aq) is completely oxidized by an aqueous solution of BrO3-(aq). Complete the balance the equation for this reaction in acidic solution. BrO3- + Sb3+ right arrow Br- + Sb5+

Explanation / Answer

Resultant half reactions: BrO3^- 6H^+ + 6e^- ---> Br^- + 3H2O Sb^3+ ---> Sb^5+ + 2e- The smallest number of common electrons is 6; multiply the second equation by 3: BrO3^- 6H^+ + 6e^- ---> Br^- + 3H2O 3Sb^3+ ---> 3Sb^5+ + 6e- Add them together: BrO3^- + 6H^+ + 3Sb^3+ ---> Br^- + 3Sb^5+ + 3H2O

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