Chemi etrv Masteringchemistry: Homework B7-T Secure https://session.masteringche

Question

Chemi etrv Masteringchemistry: Homework B7-T Secure https://session.masteringchemistry.com/myct/itemview?assignmentProblemID 76241441 CHEM 1001 Spring 2017 Signed in as Destinee Mannor Homework #7-T Problem 14.63 nmen Problem 14.63 work Part A What is the molarity of a solution of HClif 5.35 mL of the HC1 solution is titrated with 30.7mL of 0.143 M NaOH solution? twork HC (ag) t NaOH (ag) H20 +NaCl(aq) ework Express your answer with the appropriate units. Molarity Value Units Submit My Answers PEARSO cBook Pr

Explanation / Answer

Number of moles of NaOH = molarity * volume of solution in L

Number of moles of NaOH = 0.143 * 0.0307 = 0.00439 mole

from the balanced equation we can say that

1 mole of NaOH requires 1 mole of HCl so

0.00439 mole of NaOH will require 0.00439 mole of HCl

molarity of HCl = number of moles of HCl / volume of solution in L

molarity of HCl = 0.00439 mole / 0.00535 L = 0.821 M

Therefore, the molarity of HCl = 0.821 M

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.