Which arrow is the diagram represents the activation energy for revere reaction?

Question

Which arrow is the diagram represents the activation energy for revere reaction? A. A B. B C. C D. D The equilibrium constant, K_p, for the reaction CO(g) + H_2O(g) CO_2(x) + H_2(g) at 986 degree C is 0.63. A rigid cylinder at the temperature contains 1.2 atm of carbon monoxide, 0.20 atm of water vapor, 0.30 atm of carbon dioxide, and 0.27 atm of hydrogen. Is the system at equilibrium? A. Yes. B. No, the forward reaction must proceed to establish equilibrium. C. No, the reverse reaction must proceed to establish equilibrium. D. The volume of the container must be knows before deciding. E. The starting concentrations of all substances must be known before deciding. Suppose the reaction system CS_2(g) + 4H_2(g) CH_4(g) + 2H_2S(g) is at equilibrium. Which of the following statements describes the behavior of the system after the partial pressure of hydrogen, Pic, is doubled by injecting more hydrogen? (To be clear: The question is about what happens after H_2 is injected) A. In the process of reestablishing equilibrium, P_ increases. B. In the process of reestablishing equilibrium, P_ decreases. C. In the process of reestablishing equilibrium, P_ decreases. D. In the process of reestablishing equilibrium, P_ decreases. E. In the process of reestablishing equilibrium, all the partial pressures will decrease. What is the pH of 0.15 M HCl solution? A. 0.82 B. -0.82 C. 1.90 D. -1.90 E. 3.20

Explanation / Answer

(20) A - indicates activation energy.

C - indicates energy of reactants.

D - indicates energy of products

B - indicates energy change of reaction

(21)

Qp = PCO2*PH2/PCO*PH2O = 0.30 * 0.27 / (1.2*0.20) = 0.338

But Kp = 0.63, since Qp < Kp, the reaction is not at equilibrium.

(B) No, the forward reaction must proceed to establish equilibrium

(22)

Since the amount of one of the reactants increases, it shifts the equilibrium towards right side. Hence the amount of CS2 will decrease.

(C)

(23) HCl (aq.) ------------> H+ (aq.) + Cl- (aq.)

[H+] = 0.15 M

pH = - Log[H+] = - Log(0.15) = 0.82

(A)

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