At 25 degree C, gas in a rigid cylinder with a movable piston has a volume of 14

Question

At 25 degree C, gas in a rigid cylinder with a movable piston has a volume of 145 ml. and a pressure of 125 kPa. Then the gas is compressed to a volume of 80. mL. What is the new pressure of the gas if the temperature is held at 25 degree C? A) 69 kPa B) 93 kPa C) 160 kPa D) 230 kPa A 220.0-mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275 K. The piston is pushed in until the sample has a volume of 95.0 mL. The new temperature of the gas is 310. K. What is the new pressure of the sample? A) 51.1 kPa B) 216 kPa C) 243 kPa D) 274 kPa The volume of a sample of a gas is 1.0 liter at STP. If the pressure remains constant and the temperature is raised to 546 K, the new volume of the gas will be A) 0.25 L B) 2.0 L C) 0.50 L D) 4.0 L A sample of gas occupies 15.0 liters at a pressure of 2.00 atmospheres and a temperature of 300. K. If the pressure is lowered to 1.00 atmosphere and the temperature is raised to 400. K, the volume of the gas sample would be A) 5.63 L B) 10.0 L C) 22.5 L D) 40.0 L Gas samples A, B, and C arc contained in a system at STP. The partial pressure of sample A is 38.0 kPa and the partial pressure of sample B is 19.0 kPa. What is te partial pressure of sample C? A) 19.0 kPa B) 38.0 kPa C) 44.3 kPa D) 63.3 kPa A 300.0mL portion of H_2O is added to 300.0 ml. of 0.250 M H_2SO_4. What is the new molarity? Write a net ionic equation for the reaction of Pb(NO_3)_2 (aq) with K_2S(aq). Calculate the mass volume percent composition, or %(m/V), of 3.00 times 10^2 mL of solution containing 15.0 g of glucose. Calculate the freezing point of a 3.00 m aqueous solution of CaCl_2.

Explanation / Answer

(75) At constant temperature and number of moles,

P1V1 = P2V2

125 * 145 = P2 * 80

P2 = 226.6 kPa

(d)

(76)

Formula, P1V1 / T1 = P2V2 / T2

105 * 220 / 275 = P2 * 95.0 / 310

P2 = 274

(d)
(77)

At constant pressure and number of moles,

V1/T1 = V2/T2

1 / 273.15 = V2 / 546

V2 = 2.0 L

(b)

(78)

Using the formula,

P1V1 / T1 = P2V2 / T2

2.00 * 15.0 / 300 = 1.00 * V2 / 400.

V2 = 40.0 L

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