t Using Integrated Rate Laws The integrated rate laws for zero-, first-, and sec
ID: 530404 • Letter: T
Question
t Using Integrated Rate Laws The integrated rate laws for zero-, first-, and second order reaction may be arranged such that they resemble the equation for a straight line, mar b. Order Integrated Rate Law Graph Slope Part C The reactant concentration in a first-order reaction was 6.50x10-2 Mafter 45.0 s and 6.40x10-3 M after 90.0 s. What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. 12.10 s st Submit Hints My Answers Give Up Review Part incorrect; Try Again; 4 attempts remaining Part D The reactant concentration in a second-order reaction was 0.570 Mafter 210 s and 8.50x10 2 Mafter 900 S. What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. Value Units k2nd Submit Hints My Answers Give Up Review PartExplanation / Answer
PartC --- Using integrated rate law for Ist order reaction -
ln[A] = -kt + ln[A]o
[A]0 = initial concentration = 6.5*10-2 M
[A] = final concentration = 6.4*10-3M
t =time for concentration to change from initial to final = 90 - 45 =45s
k =rate constant
Putting quantities in integrated rate law equation to find rate constant.
ln[6.4*10-3] = -45k + ln[6.5*10-2]
k =0.05
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.