For delta T I got 9.2c For Ccal I have 18.4J/k for Ccontent it says that I need

ID: 533467 • Letter: F

Question

For delta T I got 9.2c
For Ccal I have 18.4J/k
for Ccontent it says that I need to use the mass of solution*specific heat of H2O (I used 30 ml of H2SO4 reacted with NaOH, specific heat of H2O is 4.18j/k*g)
How would I figure out DeltaHrxn?

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Explanation / Answer

1. T (of calorimeter and NaOH) before mixing

23.0C

22.1C

2. T

5.9C

9.2C

3. Heat gained by unknown (calculation 1)

739.86 J

1153.68 J

4. Heat gained by the calorimeter (calculation 2)

108.56 J

169.28 J

5. Total heat released by the reaction (calculation 3)

-848.42 J

-1322.96 J

6. Number of moles of water produced (calculation 4)

7. Hrxn

Calculation 1: Volume of solution (= volume of H2SO4 + NaOH) = 30 mL; density of solution = density of water = 1 g/mL.

Mass of solution = (volume of solution)*(density of solution) = (30 mL)*(1 g/mL) = 30 g.

Specific heat of water = specific heat of water = 4.18 J/g.K

Heat gained by unknown = (mass of solution)*(specific heat of solution)*T = (30 g)*(4.18 J/g.K)*(5.9 K) (t = T) = 739.86 J

Calculation 2: Ccal = 18.4 J/K

Heat gained by calorimeter = Ccal*T = (18.4 J/K)*(5.9 K) = 108.56 J

Calculation 3: Heat released by the reaction = -(heat gained by unknown + heat gained by the calorimeter) = -(739.86 + 108.56) J = -848.42 J

Calculation 4: The balanced chemical reaction is

H2SO4 + 2 NaOH --------> Na2SO4 + 2 H2O

1 mole H2SO4 = 2 moles NaOH = 2 moles H2O

We need to know the volume and the molarity of both H2SO4 and NaOH to answer this part and the following part.