8. Question Details (a) What is the mass, in grams, of 1.011 mol of iron (III) s

Question

8. Question Details (a) What is the mass, in grams, of 1.011 mol of iron (III) sulfate? (b) How many moles of ammonium ions are in 6.806 g of ammonium carbonate? mol (c) What is the mass, in grams, of 2.22 x 1021 molecules of aspirin, CoHgo4? 9 (d) What is the molar mass of diazepam (Valium®) if 0.1671 mol has a mass of 47.58 g? 4.0 g/mol Question Details Calculate the following quantities. (See the periodic table.) (a) mass, in grams, of 3.43 x 10% mol of CdS (b) number of moles of NH4C in 70.5 g of this substance mol (c) number of molecules in 8.843 x 10-2 mol C6H6 molecules (d) number of O atoms in 4.65 x 10 mol A(N03)3 o atoms

Explanation / Answer

Iron(iii) sulfate is Fe2(SO4)3, atomic weights :Fe= 56, S= 32, O= 16

molar mass of Fe2(SO4)3= 2*56+3*(32+64)= 400 g/mole

mass in 1.011 mole of Fe2(SO4)3= moles* molar mass= 1.011*400 =404.4 gm

2. amonium Carbonate is (NH4)2CO3, atomic weights : N= 14, H=1, C=12, O=16

molar mass = 2*(14+4)+12+48= 96 g/mole, moles in 6.806 gm= mass/molar mass= 6.806/96=0.07089

3.

Atomic weights : C= 12, H=1, O= 16

Molar mass of Aspirin = 9*12+8*1+4*16=180 g/mole

6.023*1023 molecules are there in 1 mole of any substance

2.22*1021 molecules are there in 2.22*1021/(6.023*1023) =0.0037

Moles= mass/molar mass, mass= moles* molar mass =0.0037*180 gm =0.666gm

4

moles= mass/molar mass = 47.58/0.1671 g/mole =284.74 g/mole

5.

Atomic weights : Cd = 112 and S= 32

Molar mass of CdS= 112+48= 160 g/mole

Moles= mass/molar mass

Mass= moles* molar mass = 3.43*10-2*160 =5.488 gm

6.

Atomic weights : N= 14, H=1 and Cl=35.5

Molar mass of NH4Cl= 14+4+35.5= 53.5 g/mole

Moles= mass/molar mass= 70.5/53.5 =1.32

7.

1 mole of any substance contains 6.023*1023 molecules

8.843*10-2 moles are there in 6.023*1023*8.843*10-2 molecules =58.6*1021 molecules

8.

Al(NO3)3

1 mole of Al(NO3)3 contains 9 atoms of O

4.65*10-3 moles contains 4.65*10-3*9 atoms =41.85*10-3 atom

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