Need 4 and 5. (4) Indium metal reacts with sulfur to form indium sulfide as belo

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Need 4 and 5.

(4) Indium metal reacts with sulfur to form indium sulfide as below: Suppose you need to produce 50.0g of indium sulfide. How many grams of indium do you need? (5) 3 Ba + A120; 3 BaO + 2 Al Barium metal reacts with aluminum oxide to form barium oxide and aluminum metal as above. Suppose 200.0 g of barium and 100.0 g of aluminum oxide are used. (a) Which is the limiting reactant? (Hint: Calculate the number of moles of Ba and Al0s (b) What is the theoretical yield of aluminum (in grams)? (6) Calcium reacts with iodine to form calcium iodide: Ca+12 Cal2 Suppose you use 3.00 g of calcium and 12.0 g of iodine. Which one is the limiting reagent? How many grams of calcium iodide can you theoretically get? ith iodine to form vanadium( )iodide: 2V+312 2V13 What is the percentage yield of the reaction? (8) Lanthanum burns in oxygen to form lanthanum oxide according to the following equation Suppose you react 2.00 g of lanthanum with oxygen and you obtain 2.17 g of lanthanum oxide. What is the Suppose you heat 27 0 g of vanadium with an excess of iodine and you obtained 172 g of vanadium(ll) jodide. sential C Rections in Aque canegories: clectrol Thrve Major Types to a base In an oxida beological that dissol conduct ele an insoluble reactions imolve percentage yield of the reaction?

Explanation / Answer

4)

Molar mass of In2S3,

MM = 2*MM(In) + 3*MM(S)

= 2*114.8 + 3*32.07

= 325.81 g/mol

mass of In2S3 = 50 g

molar mass of In2S3 = 325.81 g/mol

mol of In2S3 = (mass)/(molar mass)

= 50/325.81

= 0.1535 mol

According to balanced equation

mol of In formed = (16/8)* moles of In2S3

= (16/8)*0.1535

= 0.3069 mol

mass of In = number of mol * molar mass

= 0.3069*114.8

= 35.2 g

Answer: 35.2 g

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