A chemist measures the enthalpy change H during the following reaction: C6H12O6

Question

A chemist measures the enthalpy change

H

during the following reaction:

C6H12O6

3CH4

+  

3CO2

=H132.kJ

Use this information to complete the table below. Round each of your answers to the nearest

/kJmol.

C6H12O6

(s)

3CH4

(g)

+  

3CO2

(g)

=H132.kJ

A chemist measures the enthalpy change during the following reaction: C6H 1206(s)3 CH4(g) +3CO2(g) H-132.kl Use this information to complete the table below. Round each of your answers to the nearest kJ/mol reaction 2CM,06(s) 6CH4(g) + 6CO2(g) kJ 3CH4(g) + 3CO2(g) C6H12O6(s) kJ kJ

Explanation / Answer

Q1

A)

the reaction is clearly DOUBLED, therefore

HRxn new = 2x(HRxn)

HRxn new = 2x(-132)

HRxn = -264 kJ

B)

the reaciton is INVERTED, so

HRxn new = -1(HRxn)

HRxn new = -1(-132)

HRxn new = +132 kJ

C)

the reaction is now divided by 6 and inverted, so -1 (1/6)

HRxn = -1/6 * -132

HRxn = 22 kJ

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