Print Celculator Periodic Table Question 6 of 17 Map a) The kinetic data given i

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Print Celculator Periodic Table Question 6 of 17 Map a) The kinetic data given in the table are for the Rate of formation df P332 reaction catalyzed by a mutant of prostaglandin Arachidonic acid endoperoxide synthase. Focusing here on the first two columns, determine the Vmax and Km Of the enzyme. Rate of (mM) of POGwith 10 mo/m (mWmin) 12.3 0210 139 888 0.175 7.71 Number 031571 mM/ min 11.9 16.3 240 17.5 0.525 1 23 28.8 Number mM Please scroll down b) Ibuprofen is an inhibitor of prostaglandin endoperoxide synthase. By inhibiting the synthesis of prostaglandins, ibuprofen reduces inflammation and pain. Using the data in the first and third columns of the table, determine the type of inhibition that ibuprofen exerts on prostaglandin endoperoxide synthase. O uncompetitive inhibition O competitive inhibition O mixed inhibition O Previous Give up &Virw; Sclution Check Answer 0 Next -H Exit: Hint

Explanation / Answer

We know the values for the sustrate concentration and the rate of formatio, we need to change this value from s and v to 1/s and 1/v

If you plot this values you get the line weaver burk. The data 1/v is the y axis and the data 1/S is the x axis, let´s calculate the slope by choosing 2 points, i´ll choose the first and the last one

y2 - y1 = 0.03472 - 0.0813 = -0.046

x2-x1 = 0.81300813 - 5.714285714 = -4.9

m = -0.046 / -4.9 = 0.0095 this is the slope

Now let´s apply the straight line equation

y = mx + b

for the first point

0.0813 = 0.0095*5.714 + b

b = 0.0813 - 0.0095*5.714 = 0.027

b = 1/Vmax

Vmax = 37.037

slope = km / Vmax

0.0095 = Km / 37.07

Km = 0.3519

B) If you repeat this same procedure you will get that Vmax or b (lineweaver burk) is unnafected and that Km is increased therefore we can say it is a competitive inhibition

1/s 1/v 5.714285714 0.081300813 4.761904762 0.071942446 3.174603175 0.057142857 1.904761905 0.045045045 0.81300813 0.034722222

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